| 労働衛生 | 法令 | デザイン・サンプリング | 分析概論 | ||
| 問1 | 2 | 5 | 3 | 4 | |
| 問2 | 1 | 1 | 4 | 4 | |
| 問3 | 2 | 2 | 4 | 3 | |
| 問4 | 3 | 5 | 1 | 4 | |
| 問5 | 4 | 4 | 4 | 5 | |
| 問6 | 1 | 1 | 2 | 3 | |
| 問7 | 2 | 3 | 2 | 2 | |
| 問8 | 1 | 4 | 1 | 5 | |
| 問9 | 5 | 3 | 5 | 3 | |
| 問10 | 3 | 2 | 3 | 3 | |
| 問11 | 4 | 3 | 5 | 4 | |
| 問12 | 4 | 3 | 3 | 1 | |
| 問13 | 1 | 1 | 5 | 2 | |
| 問14 | 5 | 4 | 2 | 1 | |
| 問15 | 2 | 3 | 3 | 5 | |
| 問16 | 3 | 5 | 2 | 2 | |
| 問17 | 4 | 2 | 3 | 1 | |
| 問18 | 5 | 5 | 5 | 5 | |
| 問19 | 5 | 2 | 4 | 2 | |
| 問20 | 3 | 4 | 1 | 4 |
［デザイン･サンプリング］
問１５ 答３
0.2(Bq/ml)*1(ml) * 80(ml)/1(ml) / V(l) / 0.8 = 8(Bq/l)
V =
2.5(l)
問１７ 答３
25℃,1気圧のモル体積 24.5(l/mol)
24.5(l/mol) * (
0.25e-6(g/ml) * 10(ml) ) / ( 123(g/mol) * (5(ml)/10(ml) ) / V(l) ≦ 0.1e-6
V ≧
9.96(l)
問１８ 答５
A = log(M1) = log(1) = 0
B = (log(σ1))^2+0.084 =
0.301^2+0.084 = 0.175
log(EA1) = A+1.645*√B = 0.688
log(EA2) = A+1.151*B
= 0.201
［分析概論］
問４ 答4
Ka = [H{+}] [A{-}] / [HA]
[H{+}] [A{-}] = Ka * [HA] = 2e-5(mol/l) * 0.20(mol/l) = 4e-6(mol/l)^2
[H{+}] = [A{-}] = √4e-6 = 2e-3(mol/l)
問１１ 答４
CH4 + 2O2 → 2H2O +
CO2
酸素２モルに対し二酸化炭素が１モル発生する
酸素の量 0.96(g) = 32(g/mol) * 2(mol) *
α
二酸化炭素の量 x(g) = 44(g/mol) * 1(mol) * α
x = 0.66
問１３ 答２
吸光度E =
モル吸光係数k * 濃度c * 光路長d
k = E/cd = 0.200 / 4e-5(mol/l) / 1(cm) = 5e3(l/mol/cm)